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  1. Implement strStr()

Implement strStr().

Given two strings needle and haystack, return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.

Clarification:

What should we return when needle is an empty string? This is a great question to ask during an interview.

For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().

Example 1:

Input: haystack = "hello", needle = "ll"
Output: 2

Example 2:

Input: haystack = "aaaaa", needle = "bba"
Output: -1

Clarification:

1 <= haystack.length, needle.length <= 104
haystack and needle consist of only lowercase English characters.

Solution:

  • 解法一
    • 使用find method
  • 解法二
    1. 基本檢核
    2. 從頭開始直接比對needle在目標字串是否相似

code:

  • python
    class Solution:
         # 解法一
        def strStr(self, haystack: str, needle: str) -> int:
            return haystack.find(needle)
        # 解法二
        def strStr(self, haystack: str, needle: str) -> int:
            if len(needle) == 0:
                return 0
            for i in range(len(haystack)):
                if haystack[i:i+len(needle)] == needle:
                    return i
            return -1