Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.
Example 1:
Input: nums = [1,2,3,1]
Output: trueExample 2:
Input: nums = [1,2,3,4]
Output: falseExample 3:
Input: nums = [1,1,1,3,3,4,3,2,4,2]
Output: trueConstraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109- loop 比對並使用 hash
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java
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Code
class Solution { public boolean containsDuplicate_hash(int[] nums) { HashMap<Integer,Integer> resultMap = new HashMap<Integer, Integer>(); for (int i: nums){ if (resultMap.containsKey(i)){ return true; } resultMap.put(i,1); } return false; } public static boolean containsDuplicate_sorted(int[] nums) { Arrays.sort(nums); for (int i = 1; i < nums.length; i++) { if (nums[i] == nums[i - 1]) { return true; } } return false; } }
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