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226_InvertBinaryTree.py
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104 lines (89 loc) · 2.6 KB
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import collections
# Definition for a binary tree node.
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
def stringToTreeNode(input):
input = input.strip()
input = input[1:-1]
if not input:
return None
inputValues = [s.strip() for s in input.split(',')]
root = TreeNode(int(inputValues[0]))
nodeQueue = [root]
front = 0
index = 1
while index < len(inputValues):
node = nodeQueue[front]
front = front + 1
item = inputValues[index]
index = index + 1
if item != "null":
leftNumber = int(item)
node.left = TreeNode(leftNumber)
nodeQueue.append(node.left)
if index >= len(inputValues):
break
item = inputValues[index]
index = index + 1
if item != "null":
rightNumber = int(item)
node.right = TreeNode(rightNumber)
nodeQueue.append(node.right)
return root
def treeNodeToString(root):
if not root:
return "[]"
output = ""
queue = [root]
current = 0
while current != len(queue):
node = queue[current]
current = current + 1
if not node:
output += "null, "
continue
output += str(node.val) + ", "
queue.append(node.left)
queue.append(node.right)
return "[" + output[:-2] + "]"
class Solution:
# recursively
def invertTree1(self, root):
if root:
root.left, root.right = self.invertTree(root.right), self.invertTree(root.left)
return root
# BFS
def invertTree2(self, root):
queue = collections.deque([(root)])
while queue:
node = queue.popleft()
if node:
node.left, node.right = node.right, node.left
queue.append(node.left)
queue.append(node.right)
return root
# DFS
def invertTree(self, root: TreeNode) -> TreeNode:
stack = [root]
while stack:
node = stack.pop()
if node:
node.left, node.right = node.right, node.left
stack.extend([node.right, node.left])
return root
def main():
root = stringToTreeNode("[4,2,7,1,3,6,9]")
ret = Solution().invertTree2(root)
out = treeNodeToString(ret)
# Output:
# 4
# / \
# 7 2
# / \ / \
# 9 6 3 1
print(out)
if __name__ == '__main__':
main()