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010_findMedianSortedArrays.py
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72 lines (69 loc) · 2.37 KB
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class Solution:
def median(self, list1):
if len(list1) % 2 == 0:
med1 = list1[len(list1) // 2]
med2 = list1[len(list1) // 2 - 1]
return (med1 + med2) / 2
else:
med = list1[len(list1) // 2]
return med
def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:
list1 = []
tot = len(nums1) + len(nums2)
count1 = count2 = i = j = 0
if all(v == 0 for v in nums1) and all(v == 0 for v in nums2):
return 0
if nums1 == []:
return self.median(nums2)
if nums2 == []:
return self.median(nums1)
k=0
while k < tot:
if count1 < len(nums1) and nums1[i] == 0:
list1.append(0)
i+=1
count1+=1
elif count2 < len(nums2) and nums2[j] == 0:
list1.append(0)
j+=1
count2+=1
elif count1 < len(nums1) and count2 < len(nums2):
if (nums1[i] < nums2[j]) and count1 < len(nums1):
list1.append(nums1[i])
count1 += 1
i += 1
elif (nums1[i] > nums2[j]) and count2 < len(nums2):
list1.append(nums2[j])
count2 += 1
j += 1
elif (nums1[i] == nums2[j]) and count1 < len(nums1) and count2 < len(nums2):
list1.append(nums1[i])
list1.append(nums2[j])
i += 1
j += 1
k += 1
count1 += 1
count2 += 1
elif count2 == len(nums2):
list1.append(nums1[i])
i += 1
elif count1 == len(nums1):
list1.append(nums2[j])
j += 1
k+=1
return self.median(list1)
#------------------------------------------------------------------------
list1 = []
for i in nums1:
list1.append(i)
for i in nums2:
list1.append(i)
list1 = sorted(list1)
if len(list1)%2 != 0:
med1 = len(list1)//2
med11 = list1[med1]
else:
med1 = len(list1)//2
med2 = len(list1)//2 - 1
med11 = (list1[med1] + list1[med2])/2
return med11