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release 3.1.45.1
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‎SERVICE_CHANGELOG.md‎

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‎products.md‎

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‎pyproject.toml‎

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@@ -7,7 +7,7 @@ exclude = ["tccli/examples"]
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[project]
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name = "tccli"
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version = "3.1.44.1"
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version = "3.1.45.1"
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authors = [
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{ name="tencentcloudapi", email="tencentcloudapi@tencent.com" },
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]
@@ -24,7 +24,7 @@ classifiers = [
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dependencies = [
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"jmespath==0.10.0",
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"six==1.16.0",
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"tencentcloud-sdk-python>=3.1.44",
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"tencentcloud-sdk-python>=3.1.45",
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]
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[project.urls]

‎tccli/__init__.py‎

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@@ -1 +1 @@
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__version__ = '3.1.44.1'
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__version__ = '3.1.45.1'

‎tccli/examples/mongodb/v20190725/CreateBackupDBInstance.md‎

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Original file line numberDiff line numberDiff line change
@@ -1,22 +1,21 @@
1-
**Example 1: 备份实例接口**
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**Example 1: 发起备份任务**
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备份实例接口
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Input:
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77
```
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tccli mongodb CreateBackupDBInstance --cli-unfold-argument \
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--InstanceId cmgo-ayxpky6l \
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--BackupRemark remarkInfo \
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--InstanceId cmgo-xxxxxx \
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--BackupMethod 0
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```
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Output:
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```
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{
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"Response": {
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"AsyncRequestId": "1680780049",
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"RequestId": "1df930fb-eb7e-4e3f-bcab-15a1aa5fede0"
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"AsyncRequestId": "1750660112000249",
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"RequestId": "fa4e07a8-4452-4490-94f4-bbac1f220256"
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}
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}
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```

‎tccli/examples/mongodb/v20190725/DescribeBackupRules.md‎

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Original file line numberDiff line numberDiff line change
@@ -1,22 +1,35 @@
1-
**Example 1: 查询实例的自动备份规则信息**
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**Example 1: 获取实例备份规则**
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23

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查询实例的自动备份规则信息
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Input:
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77
```
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tccli mongodb DescribeBackupRules --cli-unfold-argument \
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--InstanceId cmgo-9d0p****
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--InstanceId cmgo-xxxxx
1010
```
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Output:
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```
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{
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"Response": {
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"ActiveWeekdays": "0,1,2,3,4,5,6",
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"AlertThreshold": 0,
18+
"BackupFrequency": 12,
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"BackupMethod": 0,
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"BackupSaveTime": 7,
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"BackupTime": 1,
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"RequestId": "07ec4290-d682-11ed-aa06-f56fb86dae78"
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"BackupTime": 0,
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"BackupTotalSize": {
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"FreeQuota": 10737418240,
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"OplogSize": 602372,
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"SnapshotSize": 28916
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},
27+
"BackupVersion": 1,
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"LongTermActiveDays": "",
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"LongTermExpiredDays": 0,
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"LongTermInterval": "",
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"OplogExpiredDays": 0,
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"RequestId": "b544304c-e8eb-4819-8715-05a005c010ca"
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}
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}
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```

‎tccli/examples/mongodb/v20190725/SetBackupRules.md‎

Lines changed: 6 additions & 7 deletions
Original file line numberDiff line numberDiff line change
@@ -1,24 +1,23 @@
1-
**Example 1: 设置实例的自动备份规则**
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**Example 1: 设置备份规则**
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Input:
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```
88
tccli mongodb SetBackupRules --cli-unfold-argument \
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--InstanceId cmgo-******** \
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--BackupFrequency 24 \
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--BackupTime 22 \
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--BackupMethod 1 \
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--InstanceId cmgo-xxxxxx \
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--BackupMethod 0 \
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--BackupFrequency 12 \
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--BackupRetentionPeriod 7 \
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--Notify True
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--BackupVersion 1
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```
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Output:
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```
1918
{
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"Response": {
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"RequestId": "58f3a6a0-2330-11ef-ad75-7139c2c3f68c"
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"RequestId": "1e9c4e16-f7a5-4db1-8978-3f92e8ca4790"
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}
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}
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```

‎tccli/examples/monitor/v20230616/CreateNoticeContentTmpl.md‎

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**Example 1: 创建模板**
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测试环境真实请求
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Input:
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```
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tccli monitor CreateNoticeContentTmpl --cli-unfold-argument \
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--TmplName Eric-test-1117-2236 \
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--MonitorType MT_QCE \
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--TmplLanguage en \
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--TmplContents.QCloudYehe.0.MatchingStatus Trigger \
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--TmplContents.QCloudYehe.0.Template.Email.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
14+
--TmplContents.QCloudYehe.0.Template.Email.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ== \
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--TmplContents.QCloudYehe.0.Template.QYWX.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.QCloudYehe.0.Template.QYWX.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ== \
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--TmplContents.QCloudYehe.0.Template.SMS.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.QCloudYehe.0.Template.SMS.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ== \
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--TmplContents.QCloudYehe.0.Template.Voice.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.QCloudYehe.0.Template.Voice.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ== \
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--TmplContents.QCloudYehe.0.Template.Site.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.QCloudYehe.0.Template.Site.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ== \
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--TmplContents.QCloudYehe.0.Template.Andon.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.QCloudYehe.0.Template.Andon.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ== \
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--TmplContents.WeWorkRobot.0.MatchingStatus Trigger \
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--TmplContents.WeWorkRobot.0.Template.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.DingDingRobot.0.MatchingStatus Trigger \
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--TmplContents.DingDingRobot.0.Template.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.DingDingRobot.0.Template.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ== \
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--TmplContents.FeiShuRobot.0.MatchingStatus Trigger \
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--TmplContents.FeiShuRobot.0.Template.ContentTmpl RXJpY+a1i+ivleaooeadv3t7LlRlc3R9fQrov5nmmK/mjaLooYzlkI7nmoTlhoXlrrl7ey5UZXN0fX0= \
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--TmplContents.FeiShuRobot.0.Template.TitleTmpl RXJpY+a1i+ivleagh+mimOaooeadv3t7LlRlc3R9fQ==
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```
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Output:
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```
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{
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"Response": {
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"RequestId": "aae79e81-4824-4b97-9307-2c7ff8f73e2e",
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"TmplID": "ntpl-3r1spzjn"
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}
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}
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```
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‎tccli/examples/ocr/v20181119/DescribeQuestionMarkAgentJob.md‎

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**Example 1: 成功示例**
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Input:
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```
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tccli ocr DescribeQuestionMarkAgentJob --cli-unfold-argument \
9+
--JobId 1410888033157898240
10+
```
11+
12+
Output:
13+
```
14+
{
15+
"Response": {
16+
"Angle": 0,
17+
"ErrorCode": "",
18+
"ErrorMessage": "",
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"JobStatus": "DONE",
20+
"MarkInfos": [
21+
{
22+
"AnswerInfos": [],
23+
"MarkInfos": [
24+
{
25+
"AnswerInfos": [
26+
{
27+
"AnswerAnalysis": "首先将除法转化为乘法，对分子分母因式分解后约分，正确计算过程为$\\frac{2}{a-1}\\div\\frac{2a-4}{a^2-1}=\\frac{2}{a-1}\times\\frac{(a+1)(a-1)}{2(a-2)}=\\frac{a+1}{a-2}$，手写答案最后一步分母错误。",
28+
"HandwriteInfo": "$\\frac{2}{a-1}\\div\\frac{2a-4}{a^2-1}=\\frac{2}{a-1}\times\\frac{(a+1)(a-1)}{2(a-2)}=\\frac{a+1}{a+2}$",
29+
"HandwriteInfoPositions": [
30+
113,
31+
648,
32+
558,
33+
648,
34+
558,
35+
698,
36+
113,
37+
698
38+
],
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"IsCorrect": false,
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"KnowledgePoints": [],
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"RightAnswer": ""
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}
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],
44+
"MarkInfos": [],
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"MarkItemTitle": "(1)小琪猜测,墨水遮住的内容是“2a”,请你根据小琪的猜测完成计算;"
46+
},
47+
{
48+
"AnswerInfos": [
49+
{
50+
"AnswerAnalysis": "设被墨水遮住的部分为A，根据题意$\\frac{2}{a-1}\\div\\frac{A-4}{a^2-1}=\\frac{1}{a-2}$，先将除法转化为乘法，得到$\\frac{2}{a-1}\times\\frac{(a+1)(a-1)}{A-4}=\\frac{1}{a-2}$，化简后求解A，正确过程为：$\\frac{2(a+1)}{A-4}=\\frac{1}{a-2}$，交叉相乘得$A-4=2(a+1)(a-2)=2(a^2-a-2)=2a^2-2a-4$，所以$A=2a^2-2a$，手写答案计算错误，没有正确求出被遮住的二次二项式。",
51+
"HandwriteInfo": "$\\frac{2}{a-1}\\div\\frac{1}{a-2}=\\frac{2(a-2)}{a-1}=\\frac{2(a-2)(a+1)}{a^2-1}=\\frac{2a^2-2a-2}{a^2-1}$",
52+
"HandwriteInfoPositions": [
53+
164,
54+
698,
55+
450,
56+
698,
57+
450,
58+
855,
59+
164,
60+
855
61+
],
62+
"IsCorrect": false,
63+
"KnowledgePoints": [],
64+
"RightAnswer": ""
65+
}
66+
],
67+
"MarkInfos": [],
68+
"MarkItemTitle": "(2)第二天,小琪的同桌告诉她,这道题被墨水遮住的是一个二次二项式,并且这道题的标准答案是$\\frac{1}{a-2}$,请你通过计算说明墨水遮住的内容是什么."
69+
}
70+
],
71+
"MarkItemTitle": "1. 小琪在做作业时发现有一道题的一部分被墨水遮住了,如图所示。计算: $\\frac{2}{a-1}\\div\\frac{▄-4}{a^2-1}$."
72+
},
73+
{
74+
"AnswerInfos": [],
75+
"MarkInfos": [
76+
{
77+
"AnswerInfos": [
78+
{
79+
"AnswerAnalysis": "先根据垂直的性质得到∠A=∠B=90°，再结合运动速度和时间算出AP、BQ、BP的长度，得到BP=AC，然后利用SAS证明△ACP≅△BPQ，最后利用全等三角形的性质和直角三角形的两个锐角互余，推出∠CPQ=90°，从而得到PC⊥PQ。",
80+
"HandwriteInfo": "全等，PC⊥PQ。∵AC⊥AB，BD⊥AB ∴∠A=∠B=90°。∵AP=BQ=2 ∴BP=5 ∴BP=AC。在△ACP和△BPQ中，{AP=BQ，∠A=∠B，AC=BP ∴△ACP≅△BPQ(SAS)。∴∠C=∠BPQ。∵∠C+∠APC=90° ∴∠BPQ+∠APC=90°。∴PC⊥PQ。",
81+
"HandwriteInfoPositions": [
82+
595,
83+
440,
84+
905,
85+
440,
86+
905,
87+
847,
88+
595,
89+
847
90+
],
91+
"IsCorrect": true,
92+
"KnowledgePoints": [],
93+
"RightAnswer": ""
94+
}
95+
],
96+
"MarkInfos": [],
97+
"MarkItemTitle": "(1)若点Q的运动速度与点P的运动速度相等,当t=1时,判断△ACP与△BPQ是否全等,并判断此时线段PC和线段PQ的位置关系,请分别说明理由."
98+
},
99+
{
100+
"AnswerInfos": [
101+
{
102+
"AnswerAnalysis": "本题需要分两种情况讨论△ACP与△BPQ全等的情况：情况一：△ACP≅△BPQ，此时AC=BP，AP=BQ；情况二：△ACP≅△BQP，此时AC=BQ，AP=BP。学生只考虑了其中一种情况，答案不完整。",
103+
"HandwriteInfo": "若△ACP≅△BPA，则AC=BP，AP=BQ，即{5=7-2t，2t=xt，解得{x=2，t=1。当x=2时，△ACP与△BPQ全等。",
104+
"HandwriteInfoPositions": [
105+
595,
106+
440,
107+
905,
108+
440,
109+
905,
110+
847,
111+
595,
112+
847
113+
],
114+
"IsCorrect": false,
115+
"KnowledgePoints": [],
116+
"RightAnswer": ""
117+
}
118+
],
119+
"MarkInfos": [],
120+
"MarkItemTitle": "(2)如图②,若将“AC⊥AB,BD⊥AB”改为“∠CAB=∠DBA”,点Q的运动速度为xcm/s,其他条件不变,当x的值为多少时,△ACP与△BPQ全等?"
121+
}
122+
],
123+
"MarkItemTitle": "如图①,AB=7cm,AC⊥AB,BD⊥AB,垂足分别为A,B,AC=5cm.点P在线段AB上以2cm/s的速度由点A向点B运动,同时点Q在射线BD上运动,它们运动的时间为ts(当点P运动结束时,点Q运动随之结束)."
124+
},
125+
{
126+
"AnswerInfos": [],
127+
"MarkInfos": [],
128+
"MarkItemTitle": "单题跨页题型，完整题目批改内容已经显示在上一题"
129+
},
130+
{
131+
"AnswerInfos": [
132+
{
133+
"AnswerAnalysis": "通过证明Rt△BOF和Rt△COE全等，得到∠FBO=∠ECO，再结合OB=OC推出∠OBC=∠OCB，进而得到∠ABC=∠ACB，最后根据等角对等边证明AB=AC，整个证明过程逻辑严谨，步骤正确。",
134+
"HandwriteInfo": "证:在Rt△BOF和Rt△COE中\n{OF=OE\nOB=OC.\n∴Rt△BOF≅Rt△COE\n∴∠FBO=∠ECO\n∵OB=OC\n∴∠OBC=∠OCB\n∴∠FBO+∠OBC=∠ECO+∠OCB即∠ABC=∠ACB\n∴AB=AC .",
135+
"HandwriteInfoPositions": [
136+
595,
137+
934,
138+
1003,
139+
934,
140+
1003,
141+
1282,
142+
595,
143+
1282
144+
],
145+
"IsCorrect": true,
146+
"KnowledgePoints": [],
147+
"RightAnswer": ""
148+
}
149+
],
150+
"MarkInfos": [],
151+
"MarkItemTitle": "3. 如图，△ABC内部一点O到两边AB,AC所在直线的距离相等，且OB=OC.求证:AB=AC."
152+
}
153+
],
154+
"RequestId": "5c0fb341-3122-409e-ba5d-12f888397057"
155+
}
156+
}
157+
```
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