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SequentParser.ts
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36 lines (30 loc) · 1.53 KB
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/*
Parser for sequents
Copyright (C) 2025 Andreas Kovalski
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
*/
/**
* Takes the user input from the web page, and tries to return a sequent if input is valid
* @param sequent The user input
* @returns A {@link Sequent} if user input is a valid sequent
* @throws An error if the input is not syntactically correct
*/
function parseSequent(sequent : string){
const cedents = sequent.split("=>")
if(cedents.length !== 2)
throw new Error("Sequent must have exacly one sequent arrow, but found "+ (cedents.length-1))
const [antecedentFormulaStrings,succedentFormulaStrings] = cedents.map(cedent => cedent.split(","))
return new Sequent(
antecedentFormulaStrings.filter(formulaString => formulaString.trim() !== "").map(formulaString => parseFormula(formulaString)),
succedentFormulaStrings.filter(formulaString => formulaString.trim() !== "").map(formulaString => parseFormula(formulaString)).reverse(), //the succedent is filpped
)
}