TooManyFllors.cpp

// Too many Floors Problem Code: FLOORS
// Add problem to Todo list
// Submit
// Chef and Chefina are residing in a hotel.

// There are 10 floors in the hotel and each floor consists of 10 rooms.

// Floor 1 consists of room numbers 1 to 10.
// Floor 2 consists of room numbers 11 to 20.
// …
// Floor i consists of room numbers 10⋅(i−1)+1 to 10⋅i.
// You know that Chef's room number is X while Chefina's Room number is Y.
// If Chef starts from his room, find the number of floors he needs to travel to reach Chefina's room.

// Input Format
// First line will contain T, number of test cases. Then the test cases follow.
// Each test case contains of a single line of input, two integers X,Y, the room numbers of Chef and Chefina respectively.
// Output Format
// For each test case, output the number of floors Chef needs to travel to reach Chefina's room.

// Constraints
// 1≤T≤1000
// 1≤X,Y≤100
// X≠Y
// Sample Input 1 
// 4
// 1 100
// 42 50
// 53 30
// 81 80
// Sample Output 1 
// 9
// 0
// 3
// 1
// Explanation
// Test Case 1: Since Room 1 is on 1st floor and Room 100 is on 10th floor, Chef needs to climb 9 floors to reach Chefina's Room.

// Test Case 2: Since Room 42 is on 5th floor and Room 50 is also on 5th floor, Chef does not need to climb any floor.

// Test Case 3: Since Room 53 is on 6th floor and Room 30 is on 3rd floor, Chef needs to go down 3 floors to reach Chefina's Room.

// Test Case 4: Since Room 81 is on 9th floor and Room 80 is on 8th floor, Chef needs to go down 1 floors to reach Chefina's Room.
#include <iostream>
using namespace std;

int main() {
    int t;
    cin>>t;
    while(t--)
    {
        int x,y;
        cin>>x>>y;
        int a=0;
        int b=0;
        a=a+(x/10);
        if(x%10!=0)
        a++;
        b=b+(y/10);
         if(y%10!=0)
         b++;
       cout<<abs(a-b)<<endl;
    }
	// your code goes here
	return 0;
}