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4-1.sql
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993 lines (928 loc) · 21.9 KB
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USE Northwind
-- I --------------------------------------------------
-- 1. Podaj łączną wartość zamówienia o numerze 10250 (uwzględnij cenę za przesyłkę)
SELECT
SUM(od.UnitPrice * od.Quantity * (1 - od.Discount) + o
.Freight) AS Price
-- źle to jest bo się freight dodaje do każdego od.OrderID czyli nalicza do jednego zamówienia kilka razy
FROM
Orders AS o
JOIN [Order Details] AS od
ON o.OrderID = od.OrderID
AND o.OrderID = 10250
SELECT
(SELECT
SUM(od.UnitPrice * od.Quantity * (1 - od.Discount))
FROM
[Order Details] AS od
WHERE o.OrderID = od.OrderID
) + o.Freight AS Price
FROM
Orders AS o
WHERE o.OrderID = 10250
-- 2. Podaj łączną wartość każdego zamówienia (uwzględnij cenę za przesyłkę)
SELECT
CONVERT(
MONEY,
(SELECT
SUM(od.UnitPrice * od.Quantity * (1 - od.Discount))
FROM
[Order Details] AS od
WHERE o.OrderID = od.OrderID
) + o.Freight ) AS Price
FROM
Orders AS o
-- 3. Dla każdego produktu podaj maksymalną wartość zakupu tego produktu
SELECT
p.ProductName
,(SELECT
TOP 1
SUM(od.UnitPrice * od.Quantity * (1 - od.Discount)) AS [Value]
FROM
[Order Details] AS od
WHERE p.ProductID = od.ProductID
GROUP BY od.OrderID
ORDER BY [Value]
) AS [MaxValue]
FROM
Products AS p
ORDER BY [MaxValue] DESC
-- 4. Dla każdego produktu podaj maksymalną wartość zakupu tego produktu w 1997r
SELECT
p.ProductName
,(SELECT
TOP 1
SUM(od.UnitPrice * od.Quantity * (1 - od.Discount)) AS [Value]
FROM
[Order Details] AS od
JOIN Orders AS o
ON o.OrderID = od.OrderID
AND YEAR(o.OrderDate) = 1997
WHERE p.ProductID = od.ProductID
GROUP BY od.OrderID
ORDER BY [Value]
) AS [MaxValue]
FROM
Products AS p
ORDER BY [MaxValue] DESC
-- II --------------------------------------------------
-- 1. Dla każdego klienta podaj łączną wartość jego zamówień (bez opłaty za przesyłkę) z 1996r
;WITH
Price
AS
(
SELECT
SUM(od.UnitPrice * od.Quantity * (1 - od.Discount)) AS sum
,od.OrderID
FROM
[Order Details] AS od
GROUP BY od.OrderID
)
SELECT
SUM(p.sum)
,o.CustomerID
FROM
Orders AS o
JOIN Price AS p
ON o.OrderID = p.OrderID
GROUP BY o.CustomerID
-- 2. Dla każdego klienta podaj łączną wartość jego zamówień (uwzględnij opłatę za przesyłkę) z 1996r
;WITH
Price
AS
(
SELECT
SUM(od.UnitPrice * od.Quantity * (1 - od.Discount)) AS sum
,od.OrderID
FROM
[Order Details] AS od
GROUP BY od.OrderID
)
SELECT
SUM(p.sum + o.Freight)
,o.CustomerID
FROM
Orders AS o
JOIN Price AS p
ON o.OrderID = p.OrderID
GROUP BY o.CustomerID
-- 3. Dla każdego klienta podaj maksymalną wartość zamówienia złożonego przez tego klienta w 1997r
;WITH
Price
AS
(
SELECT
SUM(od.UnitPrice * od.Quantity *(1 - od.Discount)
) AS sum
,od.OrderID
FROM
[Order Details] AS od
GROUP BY od.OrderID
)
SELECT
SUM(p.sum + o.Freight) AS Price
,o.CustomerID
FROM
Orders AS o
JOIN Price AS p
ON o.OrderID = p.OrderID
AND YEAR(o.OrderDate) = 1997
GROUP BY o.CustomerID
-- III --------------------------------------------------
-- 1. Dla każdego dorosłego członka biblioteki podaj jego imię, nazwisko oraz liczbę jego dzieci.
USE library
;WITH
parents
AS
(
SELECT
COUNT(*) AS childCount
,j.adult_member_no AS parent_no
FROM
juvenile AS j
GROUP BY j.adult_member_no
)
SELECT
m.lastname
,m.firstname
,ISNULL(p.childCount, 0) AS childCount
FROM
adult AS a
JOIN member AS m
ON a.member_no = m.member_no
LEFT JOIN parents AS p
ON a.member_no = p.parent_no
;
-- 2. Dla każdego dorosłego członka biblioteki podaj jego imię, nazwisko, liczbę jego dzieci, liczbę zarezerwowanych książek oraz liczbę wypożyczonych książek.
USE library
;WITH
reservated
AS
(
SELECT
COUNT(*) AS reservatedCount
,member_no AS member_no
FROM
reservation
GROUP BY member_no
)
,loaned
AS
(
SELECT
COUNT(*) AS loanedCount
,member_no AS member_no
FROM
loan
GROUP BY member_no
)
,loanReserved
AS
(
SELECT
m.member_no AS member_no
,ISNULL(r.reservatedCount,0) AS reservatedCount
,ISNULL(l.loanedCount,0) AS loanedCount
FROM
member AS m
LEFT JOIN reservated AS r
ON m.member_no = r.member_no
LEFT JOIN loaned AS l
ON m.member_no = l.member_no
)
,children
AS
(
SELECT
COUNT(*) AS childCount
,adult_member_no AS adult_member_no
FROM
juvenile AS j
GROUP BY adult_member_no
)
SELECT
m.lastname
,m.firstname
,c.childCount
,lr.loanedCount
,lr.reservatedCount
FROM
adult AS a
JOIN member AS m
ON a.member_no = m.member_no
LEFT JOIN children AS c
ON a.member_no = c.adult_member_no
JOIN loanReserved AS lr
ON a.member_no = lr.member_no
-- 3. Dla każdego dorosłego członka biblioteki podaj jego imię, nazwisko, liczbę jego dzieci, oraz liczbę książek zarezerwowanych i wypożyczonych przez niego i jego dzieci.
USE library
;WITH
reservated
AS
(
SELECT
COUNT(*) AS reservatedCount
,member_no AS member_no
FROM
reservation
GROUP BY member_no
)
,loaned
AS
(
SELECT
COUNT(*) AS loanedCount
,member_no AS member_no
FROM
loan
GROUP BY member_no
)
,loanReserved
AS
(
SELECT
m.member_no AS member_no
,ISNULL(r.reservatedCount,0) AS reservatedCount
,ISNULL(l.loanedCount,0) AS loanedCount
FROM
member AS m
LEFT JOIN reservated AS r
ON m.member_no = r.member_no
LEFT JOIN loaned AS l
ON m.member_no = l.member_no
)
,children
AS
(
SELECT
COUNT(*) AS childCount
,SUM(lr.loanedCount) AS loanedCount
,SUM(lr.reservatedCount) AS reservatedCount
,adult_member_no AS adult_member_no
FROM
juvenile AS j
JOIN loanReserved AS lr
ON j.member_no = lr.member_no
GROUP BY adult_member_no
)
SELECT
m.lastname
,m.firstname
,c.childCount
,lr.loanedCount + c.loanedCount AS loanedCount
,lr.reservatedCount + c.reservatedCount AS reservatedCount
FROM
adult AS a
JOIN member AS m
ON a.member_no = m.member_no
LEFT JOIN children AS c
ON a.member_no = c.adult_member_no
JOIN loanReserved AS lr
ON a.member_no = lr.member_no
SELECT
COUNT(*)
FROM
reservation
-- 2000
-- reservation 2160
-- SELECT
-- SUM(lr.loanedCount) AS loanedCount -- 1000
-- ,SUM(lr.reservatedCount) AS reservatedCount
-- -- 1082
-- -- SUM(c.loanedCount) AS loanedCount 1000
-- -- ,SUM(c.reservatedCount) AS reservatedCount 1078
-- FROM
-- adult AS a
-- JOIN member AS m
-- ON a.member_no = m.member_no
-- LEFT JOIN children AS c
-- ON a.member_no = c.adult_member_no
-- JOIN loanReserved AS lr
-- ON a.member_no = lr.member_no
USE library
-- ,children
-- AS
-- (
-- SELECT
-- COUNT(*) AS childCount
-- ,SUM(lr.reservatedCount) AS reservatedCount
-- ,SUM(lr.loanedCount) AS loanedCount
-- ,adult_member_no AS parent_no
-- FROM
-- juvenile AS j
-- JOIN loanReserved AS lr ON j.member_no = lr.member_no
-- GROUP BY adult_member_no
-- )
;WITH
loaned
AS
(
SELECT
COUNT(*) AS loanedCount
,member_no AS loaner_no
FROM
loan
GROUP BY member_no
)
,reservated
AS
(
SELECT
COUNT(*) AS reservatedCount
,member_no AS reservator_no
FROM
reservation
GROUP BY member_no
)
,loanReserved
AS
(
SELECT
m.member_no AS member_no
,l.loanedCount AS loanedCount
,r.reservatedCount AS reservatedCount
FROM
member AS m
JOIN reservated AS r
ON m.member_no = r.reservator_no
JOIN loaned AS l
ON m.member_no = l.loaner_no
)
SELECT
m.lastname
,m.firstname
,reservatedCount
,lr.loanedCount
FROM
adult AS a
JOIN member AS m
ON a.member_no = m.member_no
LEFT JOIN loanReserved AS lr
ON a.member_no = lr.member_no
;
-- 4. Dla każdego tytułu książki podaj ile razy ten tytuł był wypożyczany w 2001r
USE library
SELECT
COUNT(*) AS loanCount
,t.title
FROM
title AS t
JOIN loanhist AS l
ON t.title_no = l.title_no
AND YEAR(l.in_date) = 2001
GROUP BY t.title_no, t.title
-- 5. Dla każdego tytułu książki podaj ile razy ten tytuł był wypożyczany w 2002r
SELECT
COUNT(*) AS loanCount
,t.title
FROM
title AS t
JOIN loanhist AS l
ON t.title_no = l.title_no
AND YEAR(l.in_date) = 2002
GROUP BY t.title_no, t.title
-- IV --------------------------------------------------
-- 1. Czy są jacyś klienci którzy nie złożyli żadnego zamówienia w 1997 roku, jeśli tak TO pokaż ich dane adresowe
;
USE Northwind
SELECT
c.Address
,c.City
,c.PostalCode
,c.Country
FROM
Customers AS c
LEFT JOIN Orders AS o
ON c.CustomerID = o.CustomerID
AND YEAR(o.OrderDate) = 1997
WHERE o.CustomerID IS NULL
-- 2. Wybierz nazwy i numery telefonów klientów , którym w 1997 roku przesyłki dostarczała firma United Package.
SELECT
c.CompanyName
,c.ContactName
,c.Phone
FROM
Customers AS c
WHERE c.CustomerID IN (
SELECT
o.CustomerID
FROM
Orders AS o
WHERE YEAR(o.OrderDate) = 1997 AND o.ShipVia IN (
SELECT
s.ShipperID
FROM
Shippers AS s
WHERE s.CompanyName = 'United Package'
)
)
SELECT
c.CompanyName
,c.ContactName
,c.Phone
FROM
Customers AS c
WHERE c.CustomerID IN (
SELECT
o.CustomerID
FROM
Orders AS o
JOIN Shippers AS s
ON o.ShipVia = s.ShipperID
AND YEAR(o.OrderDate) = 1997
AND s.CompanyName = 'United Package'
)
-- 3. Wybierz nazwy i numery telefonów klientów , którym w 1997 roku przesyłek nie dostarczała firma United Package.
SELECT
c.CompanyName
,c.ContactName
,c.Phone
FROM
Customers AS c
WHERE c.CustomerID NOT IN (
SELECT
o.CustomerID
FROM
Orders AS o
WHERE YEAR(o.OrderDate) = 1997 AND o.ShipVia IN (
SELECT
s.ShipperID
FROM
Shippers AS s
WHERE s.CompanyName = 'United Package'
)
)
-- 4. Wybierz nazwy i numery telefonów klientów, którzy kupowali produkty z kategorii Confections.
SELECT
c.CompanyName
,c.ContactName
,c.Phone
FROM
Customers AS c
WHERE c.CustomerID IN (
SELECT
o.CustomerID
FROM
Orders AS o
JOIN [Order Details] AS od
ON o.OrderID = od.OrderID
JOIN Products AS p
ON od.ProductID = p.ProductID
JOIN Categories AS ca
ON p.CategoryID = ca.CategoryID
AND CategoryName = 'Confections'
)
-- 5. Wybierz nazwy i numery telefonów klientów, którzy nie kupowali produktów z kategorii Confections.
SELECT
c.CompanyName
,c.ContactName
,c.Phone
FROM
Customers AS c
WHERE c.CustomerID NOT IN (
SELECT
o.CustomerID
FROM
Orders AS o
JOIN [Order Details] AS od
ON o.OrderID = od.OrderID
JOIN Products AS p
ON od.ProductID = p.ProductID
JOIN Categories AS ca
ON p.CategoryID = ca.CategoryID
AND CategoryName = 'Confections'
)
-- 6. Wybierz nazwy i numery telefonów klientów, którzy w 1997r nie kupowali produktów z kategorii Confections.
SELECT
c.CompanyName
,c.ContactName
,c.Phone
FROM
Customers AS c
WHERE c.CustomerID NOT IN (
SELECT
o.CustomerID
FROM
Orders AS o
JOIN [Order Details] AS od
ON o.OrderID = od.OrderID
AND YEAR(o.OrderDate) = 1997
JOIN Products AS p
ON od.ProductID = p.ProductID
JOIN Categories AS ca
ON p.CategoryID = ca.CategoryID
AND CategoryName = 'Confections'
)
-- V --------------------------------------------------
-- 1. Podaj wszystkie produkty których cena jest mniejsza niż średnia cena produktu
SELECT
p.*
FROM
Products AS p
WHERE p.UnitPrice < (SELECT
avg(p1.UnitPrice)
FROM
Products AS p1
)
-- 2. Podaj wszystkie produkty których cena jest mniejsza niż średnia cena produktu danej kategorii
SELECT
p.*
FROM
Products AS p
WHERE p.UnitPrice < (SELECT
AVG(p1.UnitPrice)
FROM
Products AS p1
WHERE p.CategoryID = p1.CategoryID
)
-- 3. Dla każdego produktu podaj jego nazwę, cenę, średnią cenę wszystkich produktów oraz różnicę między ceną produktu a średnią ceną wszystkich produktów
SELECT
p.ProductID
,p.UnitPrice - (
SELECT
avg(p1.UnitPrice)
FROM
Products AS p1
WHERE p.CategoryID = p1.CategoryID
) AS CategoryPriceDiff
,p.UnitPrice - (SELECT
avg(p1.UnitPrice)
FROM
Products AS p1
) AS PriceDiff
FROM
Products AS p
GROUP BY p.ProductID, p.CategoryID, p.UnitPrice
;
-- 4. Dla każdego produktu podaj jego nazwę kategorii, nazwę produktu, cenę, średnią cenę wszystkich produktów danej kategorii oraz różnicę między ceną produktu a średnią ceną wszystkich produktów danej kategorii
SELECT
p.ProductName
,(SELECT
c.CategoryName
FROM
Categories AS c
WHERE p.CategoryID = c.CategoryID) AS CategoryName
,p.UnitPrice - (
SELECT
avg(p1.UnitPrice)
FROM
Products AS p1
WHERE p.CategoryID = p1.CategoryID
) AS CategoryPriceDiff
,p.UnitPrice - (SELECT
avg(p1.UnitPrice)
FROM
Products AS p1
) AS PriceDiff
FROM
Products AS p
GROUP BY p.ProductID, p.ProductName, p.CategoryID, p.UnitPrice
-- VI --------------------------------------------------
-- 1. Podaj produkty kupowane przez więcej niż jednego klienta
USE Northwind
SELECT
p.ProductName
,COUNT(*) AS OrderedByClients
FROM
Orders AS o
JOIN [Order Details] AS od
ON o.OrderID = od.OrderID
JOIN Products AS p
ON od.ProductID = p.ProductID
GROUP BY od.ProductID, o.CustomerID, p.ProductName
HAVING COUNT(*) > 1
-- 2. Podaj produkty kupowane w 1997r przez więcej niż jednego klienta
SELECT
p.ProductName
,COUNT(*) AS OrderedByClients
FROM
Orders AS o
JOIN [Order Details] AS od
ON o.OrderID = od.OrderID
AND YEAR(o.OrderDate) = 1997
JOIN Products AS p
ON od.ProductID = p.ProductID
GROUP BY od.ProductID, o.CustomerID, p.ProductName
HAVING COUNT(*) > 1
-- 3. Podaj nazwy klientów którzy w 1997r kupili co najmniej dwa różne produkty z kategorii 'Confections'
;WITH
Confections
AS
(
SELECT
p.ProductID
FROM
Products AS p
JOIN Categories AS c
ON p.CategoryID = c.CategoryID
AND c.CategoryName = 'Confections'
)
,OrderConfection
AS
(
SELECT
o.CustomerID
,COUNT(*) AS OrderedProducts
FROM
[Order Details] AS od
JOIN Confections AS c
ON od.ProductID = c.ProductID
JOIN Orders AS o
ON od.OrderID = o.OrderID
GROUP BY o.CustomerID, c.ProductID
)
SELECT
CompanyName
,oc.OrderedProducts
FROM
Customers AS c
JOIN OrderConfection AS oc
ON c.CustomerID = oc.CustomerID
WHERE oc.OrderedProducts >= 2
-- VII --------------------------------------------------
-- 1. Dla każdego pracownika (imię i nazwisko) podaj łączną wartość zamówień obsłużonych przez tego pracownika, przy obliczaniu wartości zamówień uwzględnij cenę za przesyłkę
;WITH
ProductsValue
AS
(
SELECT
OrderID
,CAST(SUM((UnitPrice * Quantity) * (1 - Discount)) AS MONEY) AS [Value]
FROM
[Order Details]
GROUP BY OrderID
)
,OrdersValue
AS
(
SELECT
o.EmployeeID
,CAST(SUM(o.Freight + p.[Value])AS MONEY) AS TotalValue
FROM
Orders AS o
JOIN ProductsValue AS p
ON o.OrderID = p.OrderID
GROUP BY o.EmployeeID
)
SELECT
e.LastName
,e.FirstName
,o.TotalValue
FROM
Employees AS e
JOIN OrdersValue AS o
ON e.EmployeeID = o.EmployeeID
;
-- 2. Który z pracowników był najaktywniejszy (obsłużył zamówienia o największej wartości) w 1997r, podaj imię i nazwisko takiego pracownika
;WITH
ProductsValue
AS
(
SELECT
OrderID
,CAST(SUM((UnitPrice * Quantity) * (1 - Discount)) AS MONEY) AS [Value]
FROM
[Order Details]
GROUP BY OrderID
)
,OrdersValue
AS
(
SELECT
o.EmployeeID
,CAST(SUM(o.Freight + p.[Value])AS MONEY) AS TotalValue
FROM
Orders AS o
JOIN ProductsValue AS p
ON o.OrderID = p.OrderID
WHERE YEAR(o.OrderDate) = 1997
GROUP BY o.EmployeeID
)
SELECT
TOP 1
e.LastName
,e.FirstName
,o.TotalValue
FROM
Employees AS e
JOIN OrdersValue AS o
ON e.EmployeeID = o.EmployeeID
ORDER BY o.TotalValue DESC
;
-- 3. Ogranicz wynik z pkt 1 tylko do pracowników
-- a) którzy mają podwładnych
;WITH
Supervisors
AS
(
SELECT
DISTINCT
ReportsTo AS EmployeeID
FROM
Employees
WHERE ReportsTo IS NOT NULL
)
,ProductsValue
AS
(
SELECT
OrderID
,CAST(SUM((UnitPrice * Quantity) * (1 - Discount)) AS MONEY) AS [Value]
FROM
[Order Details]
GROUP BY OrderID
)
,OrdersValue
AS
(
SELECT
o.EmployeeID
,CAST(SUM(o.Freight + p.[Value])AS MONEY) AS TotalValue
FROM
Orders AS o
JOIN ProductsValue AS p
ON o.OrderID = p.OrderID
GROUP BY o.EmployeeID
)
SELECT
e.LastName
,e.FirstName
,o.TotalValue
FROM
Employees AS e
JOIN OrdersValue AS o
ON e.EmployeeID = o.EmployeeID
WHERE e.EmployeeID IN (SELECT
s.EmployeeID
FROM
Supervisors AS s)
;
-- b) którzy nie mają podwładnych
;WITH
Supervisors
AS
(
SELECT
DISTINCT
ReportsTo AS EmployeeID
FROM
Employees
WHERE ReportsTo IS NOT NULL
)
,ProductsValue
AS
(
SELECT
OrderID
,CAST(SUM((UnitPrice * Quantity) * (1 - Discount)) AS MONEY) AS [Value]
FROM
[Order Details]
GROUP BY OrderID
)
,OrdersValue
AS
(
SELECT
o.EmployeeID
,CAST(SUM(o.Freight + p.[Value])AS MONEY) AS TotalValue
FROM
Orders AS o
JOIN ProductsValue AS p
ON o.OrderID = p.OrderID
GROUP BY o.EmployeeID
)
SELECT
e.EmployeeID
,e.LastName
,e.FirstName
,o.TotalValue
FROM
Employees AS e
JOIN OrdersValue AS o
ON e.EmployeeID = o.EmployeeID
WHERE e.EmployeeID NOT IN (SELECT
s.EmployeeID
FROM
Supervisors AS s)
;
-- 4. Zmodyfikuj rozwiązania z pkt 3 tak aby dla pracowników pokazać jeszcze datę ostatnio obsłużonego zamówienia
;WITH
Supervisors
AS
(
SELECT
DISTINCT
ReportsTo AS EmployeeID
FROM
Employees
WHERE ReportsTo IS NOT NULL
)
,ProductsValue
AS
(
SELECT
OrderID
,CAST(SUM((UnitPrice * Quantity) * (1 - Discount)) AS MONEY) AS [Value]
FROM
[Order Details]
GROUP BY OrderID
)
,OrdersValue
AS
(
SELECT
o.EmployeeID
,CAST(SUM(o.Freight + p.[Value])AS MONEY) AS TotalValue
FROM
Orders AS o
JOIN ProductsValue AS p
ON o.OrderID = p.OrderID
GROUP BY o.EmployeeID
)
,LastOrder
AS
(
SELECT
MAX(OrderDate) AS LastDate
,EmployeeID
FROM
Orders
GROUP BY EmployeeID
)
SELECT
e.LastName
,e.FirstName
,o.TotalValue
,lo.LastDate
FROM
Employees AS e
JOIN OrdersValue AS o
ON e.EmployeeID = o.EmployeeID
JOIN LastOrder AS lo
ON e.EmployeeID = lo.EmployeeID
WHERE e.EmployeeID IN (SELECT
s.EmployeeID
FROM
Supervisors AS s)
;
-- b) którzy nie mają podwładnych
;WITH
Supervisors
AS
(
SELECT
DISTINCT
ReportsTo AS EmployeeID
FROM
Employees
WHERE ReportsTo IS NOT NULL
)
,ProductsValue
AS
(
SELECT
OrderID
,CAST(SUM((UnitPrice * Quantity) * (1 - Discount)) AS MONEY) AS [Value]
FROM
[Order Details]
GROUP BY OrderID
)
,OrdersValue
AS
(
SELECT
o.EmployeeID
,CAST(SUM(o.Freight + p.[Value])AS MONEY) AS TotalValue
FROM
Orders AS o
JOIN ProductsValue AS p
ON o.OrderID = p.OrderID
GROUP BY o.EmployeeID
)
,LastOrder
AS
(
SELECT
MAX(OrderDate) AS LastDate
,EmployeeID
FROM
Orders
GROUP BY EmployeeID
)
SELECT
e.EmployeeID
,e.LastName
,e.FirstName
,o.TotalValue
,lo.LastDate
FROM
Employees AS e
JOIN OrdersValue AS o
ON e.EmployeeID = o.EmployeeID
JOIN LastOrder AS lo
ON e.EmployeeID = lo.EmployeeID
WHERE e.EmployeeID NOT IN (SELECT
s.EmployeeID
FROM
Supervisors AS s)
;