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Fibonacci(logn)-Matrix Exponentiation.cpp
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83 lines (69 loc) · 1.66 KB
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// Fibonacci Numbers
// Using Recursion : O(2^n)
// Using Dynamic Programming : O(n)
// Using Matrix Exponentiation : O(k^3log(n)) = O(logn)
// f(n) = 1 1 ^(n-2) * f(2)
// f(n-1) 1 0 f(1)
#include<bits/stdc++.h>
using namespace std;
#define int long long
const int N = 1e5+2 , MOD = 1e9+7;
//function to multiply two square matrices O(k^3)
vector<vector<int>> multiply(vector<vector<int>> &a,vector<vector<int>> &b)
{
int n = a.size();
vector<vector<int>> ans(n,vector<int>(n,0));
for(int i=0;i<n;i++)
{
for(int j=0;j<n;j++)
{
for(int k=0;k<n;k++)
{
ans[i][j] += a[i][k]*b[k][j];
}
}
}
return ans;
}
// function to exponentiate (logn)
vector<vector<int>> matrixExponentiate(vector<vector<int>>&a,int n)
{
if(n==0)
{
int sz=a.size();
vector<vector<int>> ans(sz,vector<int>(sz,0));
for(int i=0;i<sz;i++)
{
ans[i][i]=1;
}
return ans;
}
if(n==1)
{
return a;
}
vector<vector<int>> temp = matrixExponentiate(a,n/2);
vector<vector<int>> ans = multiply(temp,temp);
if(n&1)
{
ans = multiply(ans,a);
}
return ans;
}
signed main()
{
int n;
cin>>n;
vector<vector<int> > a = {{1,1},{1,0}};
vector<vector<int> > ans = matrixExponentiate(a,n);
int sz = ans.size();
for(int i=0;i<sz;i++)
{
for(int j=0;j<sz;j++)
{
cout<<ans[i][j]<<" ";
}
cout<<endl;
}
return 0;
}