diff --git a/02_activities/assignments/DC_Cohort/One Entity-Relationship Diagram.png b/02_activities/assignments/DC_Cohort/One Entity-Relationship Diagram.png new file mode 100644 index 000000000..cd77140e9 Binary files /dev/null and b/02_activities/assignments/DC_Cohort/One Entity-Relationship Diagram.png differ diff --git a/02_activities/assignments/DC_Cohort/assignment1.sql b/02_activities/assignments/DC_Cohort/assignment1.sql index c992e3205..daeff5ece 100644 --- a/02_activities/assignments/DC_Cohort/assignment1.sql +++ b/02_activities/assignments/DC_Cohort/assignment1.sql @@ -4,17 +4,23 @@ --SELECT /* 1. Write a query that returns everything in the customer table. */ - +SELECT * +FROM customer; /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, sorted by customer_last_name, then customer_first_ name. */ - +SELECT* +FROM customer +ORDER BY customer_last_name, customer_first_name +LIMIT 10; --WHERE /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */ - +SELECT * +FROM customer_purchases +WHERE product_id IN (4,9); /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), @@ -23,11 +29,25 @@ filtered by customer IDs between 8 and 10 (inclusive) using either: 2. one condition using BETWEEN */ -- option 1 - +SELECT +customer_id, +product_id, +quantity, +cost_to_customer_per_qty, +quantity * cost_to_customer_per_qty AS price +FROM customer_purchases +WHERE customer_id >= 8 AND customer_id <= 10; -- option 2 - +SELECT +customer_id, +product_id, +quantity, +cost_to_customer_per_qty, +quantity * cost_to_customer_per_qty AS price +FROM customer_purchases +WHERE customer_id BETWEEN 8 AND 10; --CASE /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. @@ -35,19 +55,41 @@ Using the product table, write a query that outputs the product_id and product_n columns and add a column called prod_qty_type_condensed that displays the word “unit” if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */ +SELECT +product_name, +product_id, +CASE + WHEN product_qty_type LIKE '%unit%' THEN 'unit' + ELSE 'bulk' + END as product_qty_type_condensed +FROM product; /* 2. We want to flag all of the different types of pepper products that are sold at the market. add a column to the previous query called pepper_flag that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */ +SELECT +product_name, +product_id, +CASE + WHEN product_name LIKE '%pepper%' THEN 1 + ELSE 0 + END as pepper_flag + +FROM product; --JOIN /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */ - +SELECT * +FROM vendor as v +INNER JOIN vendor_booth_assignments as vb + ON v.vendor_id = vb.vendor_id +ORDER BY vendor_name, market_date; + /* SECTION 3 */ @@ -56,7 +98,11 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t /* 1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per vendor_id. */ - +SELECT +vendor_id, +COUNT (vendor_id) as num_of_booth_rented +FROM vendor_booth_assignments +GROUP BY vendor_id; /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list @@ -64,7 +110,18 @@ of customers for them to give stickers to, sorted by last name, then first name. HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */ +SELECT +customer_last_name, +customer_first_name, +ROUND(SUM(quantity*cost_to_customer_per_qty),2) as total_spend +FROM customer_purchases as cp +INNER JOIN customer as p + ON cp.customer_id = p.customer_id + +GROUP BY cp.customer_id +HAVING total_spend > 2000 +ORDER BY customer_last_name, customer_first_name; --Temp Table /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: @@ -78,8 +135,17 @@ When inserting the new vendor, you need to appropriately align the columns to be VALUES(col1,col2,col3,col4,col5) */ +DROP TABLE IF EXISTS temp.new_vendor; + +INSERT OR IGNORE INTO vendor(vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name) +VALUES (10, 'Thomass Superfood Store', 'a Fresh Focused store', 'Thomas', 'Rosental'); +CREATE TABLE temp.new_vendor AS +SELECT * +FROM vendor; + + -- Date /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.