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matrixExponentiation.cpp
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183 lines (157 loc) · 3.26 KB
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#include <bits/stdc++.h>
using namespace std;
typedef long long int lli;
#define vi vector<int>
#define vb vector<bool>
#define vs vector<string>
#define vc vector<char>
#define vp vector<pair<int, int>>
#define vvi vector<vector<int>>
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define pii pair < int, int >=
#define endl "\n"
#define forin(a, b, c) for (int(a) = (b); (a) < (c); ++(a))
#define fordec(a, b, c) for (int(a) = (b); (a) >= (c); --(a))
#define tc_ll \
lli t; \
cin >> t; \
while (t--)
#define fast \
ios_base::sync_with_stdio(0); \
cin.tie(0); \
cout.tie(0);
#define N 101
#define M 1000000007
lli mod(lli x)
{
return x >= 0 ? x : -x;
}
// also solving MPOW from SPOJ in the optimized approach
lli ar[N][N], I[N][N];
// naive approach for power funtion which takes O((dimensions^3) * (power)) i.e O((m^3) * n)
// O(m^3)
void mul(lli A[][N], lli B[][N], lli m)
{
lli res[m + 1][m + 1];
for (lli i = 0; i <= m; i++)
{
for (lli j = 0; j <= m; j++)
{
res[i][j] = 0;
}
}
for (lli i = 0; i < m; i++)
{
for (lli j = 0; j < m; j++)
{
for (lli k = 0; k < m; k++)
{
res[i][j] = (res[i][j] + ((A[i][k] % M) * (B[k][j] % M)) % M) % M;
}
}
}
for (lli i = 0; i < m; i++)
{
for (lli j = 0; j < m; j++)
{
A[i][j] = res[i][j];
}
}
}
void mpower(lli ar[][N], lli m, lli n)
{
for (lli i = 0; i < m; i++)
{
for (lli j = 0; j < m; j++)
{
if (i == j)
I[i][j] = 1;
else
I[i][j] = 0;
}
}
// prllimat(I, m);
for (lli i = 0; i < n; i++)
{
// res *= base;
mul(I, ar, m);
}
for (lli i = 0; i < m; i++)
{
for (lli j = 0; j < m; j++)
{
ar[i][j] = I[i][j];
}
}
}
void prllimat(lli ar[][N], lli m)
{
for (lli i = 0; i < m; i++)
{
for (lli j = 0; j < m; j++)
{
cout << ar[i][j] << " ";
}
cout << endl;
}
}
// optimized approach: inspired from binary exponentiation in O((m^3) * log(n))
void oppower(lli ar[][N], lli m, lli n)
{
for (lli i = 0; i < m; i++)
{
for (lli j = 0; j < m; j++)
{
if (i == j)
I[i][j] = 1;
else
I[i][j] = 0;
}
}
// prllimat(I, m);
// I is identity matrix in here
while (n)
{
if (n % 2)
{
// res = (res*base)%modulo
mul(I, ar, m);
n--;
}
else
{
// res = (A*A)%modulo
mul(ar, ar, m);
n /= 2;
}
}
for (lli i = 0; i < m; i++)
{
for (lli j = 0; j < m; j++)
{
ar[i][j] = I[i][j];
}
}
}
int main()
{
fast
tc_ll
{
lli dim, n;
cin >> dim >> n;
for (lli i = 0; i < dim; i++)
{
for (lli j = 0; j < dim; j++)
{
cin >> ar[i][j];
}
}
oppower(ar, dim, n);
prllimat(ar, dim);
}
return 0;
}