1+ """
2+ Re: Fwd: Fw: Count
3+ Given a string representing the subject line of an email, determine how many times the email has been forwarded or replied to.
4+
5+ For simplicity, consider an email forwarded or replied to if the string contains any of the following markers (case-insensitive):
6+
7+ "fw:"
8+ "fwd:"
9+ "re:"
10+ Return the total number of occurrences of these markers.
11+
12+
13+ """
14+ import unittest
15+
16+ class ReFwdFwCountTest (unittest .TestCase ):
17+
18+ def test1 (self ):
19+ self .assertEqual (email_chain_count ("Re: Meeting Notes" ), 1 )
20+
21+ def test2 (self ):
22+ self .assertEqual (email_chain_count ("Meeting Notes" ), 0 )
23+
24+ def test3 (self ):
25+ self .assertEqual (email_chain_count ("Re: re: RE: rE: Meeting Notes" ), 4 )
26+
27+ def test4 (self ):
28+ self .assertEqual (email_chain_count ("Re: Fwd: Re: Fw: Re: Meeting Notes" ), 5 )
29+
30+ def test5 (self ):
31+ self .assertEqual (email_chain_count ("re:Ref:fw:re:review:FW:Re:fw:report:Re:FW:followup:re:summary:Fwd:Re:fw:NextStep:RE:FW:re:Project:Fwd:Re:fw:Notes:RE:re:Update:FWD:Re:fw:Summary" ), 23 )
32+
33+
34+
35+ def email_chain_count (subject ):
36+ subject = subject .lower ()
37+ checkers = ["fw:" ,"fwd:" ,"re:" ]
38+ count = 0
39+ for check in checkers :
40+ count += subject .count (check )
41+
42+ return count
43+
44+ """
45+ The above solution works fine for some cases but there are issues with this code
46+
47+ 1. Overlapping markers
48+ -> "fwd:" contains "fw:"
49+ -> if the subject has "fwd:", the above code will count both "fw:" and "fwd:"
50+ Example:
51+ print(email_chain_count("Fwd: Meetig"))
52+ # Output: 2 (counts "fw:" and "fwd:")
53+
54+ # Expected: 1
55+
56+ 2. Exact matching:
57+ -> if you want to avoid double-counting, you need to ensure "fw:" and "fwd:" are treated as distinct
58+ tokens, not substrings.
59+
60+ => This solution works fine unless "fwd:" appears, where it double-count because "fw:" is a substring of "fwd:".
61+ => Regex avoids this overlap by treating each marker as a distinct option.
62+ => if the requirement is okay with the slight overcount, this version is perfectly serviceable. If you want exact correctness,
63+ regext is the safer choice.
64+
65+ """
66+
67+ import re
68+ # Corrected Version
69+ def email_chain_count (subject ):
70+
71+ markers = ["fw:" ,"fwd:" ,"re:" ]
72+
73+ pattern = re .compile (r"(fw:|fwd:|re:)" ,re .IGNORECASE )
74+
75+ matches = pattern .findall (subject )
76+
77+ return len (matches )
78+
79+ """
80+ This solution
81+
82+ => Use case-insensitive matching re.IGNORECASE in (python, /gi i JS).
83+ => Regex is the cleanest way since it handles overlapping and mixed cases.
84+ => The result is simply the length of all matches.
85+
86+ """
87+
88+
89+
90+ if __name__ == "__main__" :
91+
92+ unittest .main ()
0 commit comments