Quiz10.py

# below is the AI 1.0 code, which works but cannot handle invalid input
# if the user input something other than an integer at first, the program will break due to a ValueError,
# caused by calling int() function on an non-integer input result
#
# Your task is to use the try-except-else-finally workflow to improve the existing code
# which can detect an invalid input in the beginning, and prints our an error message: 'Please input integers only.'
# then proceed to ask the user 'Do you want to play again? (y/N):' like the original function does
def interact():
    while True:  # keep looping until user reach break statement
        try:
            user_input = int(input('Please input an integer:'))
        except ValueError:
            print("Please input integers only")
        else:     # turn the user input into an integer
            print('{} is {}.'.format(user_input, 'even' if user_input % 2 == 0 else 'odd'))     # print out the message '{user_input} is {even/odd}.'
        finally:
            user_input = input('Do you want to play again? (y/N):')
            if user_input != 'y':   # quit if the user didn't input `y`
                print('Goodbye.')
                break   # break the while loop to quit

interact()