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MaxRecursion.js
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30 lines (29 loc) · 921 Bytes
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/*
* @function maxRecursion
* @description This algorithm will find the maximum value of a array of numbers.
*
* @param {Integer[]} arr Array of numbers
* @param {Integer} left Index of the first element
* @param {Integer} right Index of the last element
*
* @return {Integer} Maximum value of the array
*/
function maxRecursion(arr, left, right) {
const len = arr.length
if (len === 0 || !arr) {
return undefined
}
if (left >= len || left < -len || right >= len || right < -len) {
throw new Error('Index out of range')
}
if (left === right) {
return arr[left]
}
// n >> m is equivalent to floor(n / pow(2, m)), floor(n / 2) in this case, which is the mid index
const mid = (left + right) >> 1
const leftMax = maxRecursion(arr, left, mid)
const rightMax = maxRecursion(arr, mid + 1, right)
// Return the maximum
return Math.max(leftMax, rightMax)
}
export { maxRecursion }