[ 命名建議 ] LeetCode 1640. Check Array Formation Through Concatenation

[LPenny-github]

原 issue:
#85

LeetCode:
https://leetcode.com/problems/check-array-formation-through-concatenation/

[ 題目看嘸 ]：
#104

---

再麻煩 @twy30 給予命名建議 orz 感激不盡

using System;

public class Solution
{
    public static bool CanFormArray(int[] arr, int[][] pieces)
    {
        int[] targetArray = arr;
        int[][] piecesOfPuzzles = pieces;
        for (int i = 0; i < piecesOfPuzzles.Length; ++i)
        {
            int firstPuzzleIndex = Array.IndexOf(targetArray, piecesOfPuzzles[i][0]);
            if (firstPuzzleIndex < 0)
            {
                return false;
            }
            for (int k = 1; k < piecesOfPuzzles[i].Length; ++k)
            {
                // targetArray = [64,4]
                // piecesOfPuzzles = [[4,64]]
                // firstPuzzleIndex = 1+1(k) >= 2(targetArray.Length)

                if (firstPuzzleIndex + k >= targetArray.Length)
                {
                    return false;
                }

                // targetArray = [64,4,32]
                // piecesOfPuzzles = [[4,64],[32]]
                // piecesOfPuzzles[0][1] = 64 
                // targetArray[ 1(firstPuzzleIndex) + 1(k) ] = 32

                if (piecesOfPuzzles[i][k] != targetArray[firstPuzzleIndex + k])
                {
                    return false;
                }
            }
        }
        return true;
    }
}

[twy30]

@LPenny-github

@

你好 😊

---

一般來說，

• 「(一整份) 拼圖」是 "jigsaw puzzle" ；也有用 jigsaw 或 puzzle 當作「拼圖」的簡稱
• "piece" 是 (某物的) 一片/一部分
• 「一塊拼圖」會稱作 "a puzzle piece"

---

        int[][] piecesOfPuzzles = pieces;

可以考慮使用 puzzlePieces 。

---

            int firstPuzzleIndex = Array.IndexOf(targetArray, piecesOfPuzzles[i][0]);

如果之前是用 puzzlePieces ，這裡我會改成 firstPieceIndex 。

可以參考看看 😊

[LPenny-github]

@twy30 感謝大大。我會努力學習 orz