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@@ -716,6 +722,7 @@ we need the following unitary transformations $\bm{U}$
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\end{align*}
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!et
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These are the gates that are relevant for the simpler two-qubit Hamiltonian of project 1.
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!split
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===== More complete list and derivations of expressions for strings of operators =====
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@@ -729,6 +736,28 @@ For a two qubit system we list here the possible transformations
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\end{align*}
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!et
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!split
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===== Additional remarks =====
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Here, the CNOT operation appears for the following reason. Each Pauli measurement that doesn't include the
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matrix is equivalent up to a unitary to
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by the earlier reasoning. The eigenvalues of
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only depend on the parity of the qubits that comprise each computational basis vector, and the controlled-not operations serve to compute this parity and store it in the first bit. Then once the first bit is measured, you can recover the identity of the resultant half-space, which is equivalent to measuring the Pauli operator.
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Also, while it can be tempting to assume that measuring
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is the same as sequentially measuring π
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and then π
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, this assumption would be false. The reason is that measuring
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projects the quantum state into either the
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or
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eigenstate of these operators. Measuring π
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and then π
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projects the quantum state vector first onto a half space of π
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and then onto a half space of π
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. As there are four computational basis vectors, performing both measurements reduces the state to a quarter-space and hence reduces it to a single computational basis vector.
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