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Update index.html
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index.html

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@@ -324,7 +324,7 @@ <h3 itemprop="name">Numeric Systems</h3>
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<summary><h3 itemprop="name">2. Equations</h3></summary>
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<section itemprop="about"itemscope itemtype="http://schema.org/LearningResource">
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<section itemprop="about" itemscope itemtype="http://schema.org/LearningResource">
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<h4 itemprop="name">= Equation</h4>
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<br>
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<p itemprop="description">The numbers or expressions of one side equal in value to the other side.
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<section itemprop="subjectOf" itemscope itemtype="http://schema.org/LearningResource" id="geometry"">
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<section itemprop="subjectOf" itemscope itemtype="http://schema.org/LearningResource" id="geometry">
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<h3 style="margin:7px" itemprop="name">The 2nd and the 3rd Powers manifesting in Geometry</h3>
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<section id="square">
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</div>
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</section>
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The square root of half of the area of the rectangle is the side length of the theoretical square that has the same area as the triangle.</p>
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<div itemprop="result" itemscope itemtype="https://schema.org/MathSolver">
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<math display="block" itemprop="mathExpression" xmlns="http://www.w3.org/1998/Math/MathML">
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<div itemprop="result">
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<p itemprop="description" style="margin:12px">The area of a triangle can also be calculated by the length of its sides.</p>
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<div itemprop="result" itemscope itemtype="https://schema.org/MathSolver">
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<math <p style="margin:12px"> xmlns="http://www.w3.org/1998/Math/MathML" >
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<div itemprop="result">
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<math style="margin:12px"> xmlns="http://www.w3.org/1998/Math/MathML">
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<math itemprop="mathExpression" display="block" xmlns="http://www.w3.org/1998/Math/MathML">
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</math>
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<math itemprop="mathExpression" display="block" xmlns="http://www.w3.org/1998/Math/MathML">
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<div itemprop="result">
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<math display="block" xmlns="http://www.w3.org/1998/Math/MathML">
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</section>
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<p style="margin:12px" itemprop="description">The area of both the square and the sum of the quadrants equals 16 right triangles with legs of a quarter, and a half of the square's sides, and its hypotenuse equal to the radius of the circle.</p>
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<div itemprop="result" itemscope itemtype="https://schema.org/MathSolver">
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<math itemprop="mathExpression" display="block" xmlns="http://www.w3.org/1998/Math/MathML">
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<math display="block" xmlns="http://www.w3.org/1998/Math/MathML">
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<section itemprop="potentialAction" itemscope itemtype="https://schema.org/SolveMathAction" id="circumference" itemref="circle">
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<h3 itemprop="eduQuestionType" style="margin:7px">Circumference of a Circle</h3>
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<meta itemprop="target" content="https://basic-geometry.github.io?q={circle_radius=1_circumference=?"}">
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<meta itemprop="target" content="https://basic-geometry.github.io?q={circle_radius=1_circumference=?}">
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<figure itemprop="image" class="imgbox" itemscope itemtype="http://schema.org/ImageObject">
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<img class="center-fit" src="circumference.jpg" alt="The circumference of a circle is derived from its area algebraically by subtracting a smaller circle and dividing the difference by the difference of the radii. Circumference = 6.4r">
@@ -2873,8 +2872,8 @@ <h4>A Rational Alternative: 3.2</h4>
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<p style="margin:12px" itemprop="description">The length of the circumference approaches 6.4 × radius as its thickness approaches 0.
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<p style="margin:12px" itemprop="description">In calculus terms:</p>
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@@ -3144,8 +3143,8 @@ <h3 itemprop="eduQuestionType" style="margin:7px">Surface Area of a Cone</h3>
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<p style="margin:12px" itemprop="description">The surface area of a cone is calculated as a circle slice with a radius equal to the slant height and the angle given by the ratio between the height and the slant height.</p>
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<math display="block" itemprop="mathExpression" xmlns="http://www.w3.org/1998/Math/MathML" >
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@@ -3242,8 +3241,8 @@ <h3 itemprop="eduQuestionType" style="margin:7px">Volume of a Sphere</h3>
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<p style="margin:12px" itemprop="description">The volume of a sphere equals the cubic value of the square root of its cross-sectional area, just like a cube.</p>
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@@ -3356,8 +3355,8 @@ <h3 itemprop="eduQuestionType" style="margin:7px">Volume of a Spherical Cap</h3>
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<p style="margin:12px" itemprop="description">One dimension of the volume of sphere formula can be adjusted to calculate the volume of a spherical cap as a distorted hemisphere.</p>
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<section itemprop="potentialAction" itemscope itemtype="https://schema.org/SolveMathAction" id="square_frustum" itemref="pyramid">
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<h3 itemprop="eduQuestionType" style="margin:12px">Volume of a horizontal square Frustum Pyramid</h3>
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<meta itemprop="target" content="https://basic-geometry.github.io?q={square_frustum_pyramid_height=3_edge_length_top=1_bottom=2_volume=?"}">
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<meta itemprop="target" content="https://basic-geometry.github.io?q={square_frustum_pyramid_height=3_edge_length_top=1_bottom=2_volume=?}">
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