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Graph_Day_4 .py
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Problem ---- Number Of Provinces (Leetcode)
There are n cities. Some of them are connected, while some are not. If city a is connected directly with city b, and city b is connected directly with city c, then city a is connected indirectly with city c.
A province is a group of directly or indirectly connected cities and no other cities outside of the group.
You are given an n x n matrix isConnected where isConnected[i][j] = 1 if the ith city and the jth city are directly connected, and isConnected[i][j] = 0 otherwise.
Return the total number of provinces.
Example 1:
Input: isConnected = [[1,1,0],[1,1,0],[0,0,1]]
Output: 2
Example 2:
Input: isConnected = [[1,0,0],[0,1,0],[0,0,1]]
Output: 3
############################################# DFS ----Solution ###################################
class Solution:
def findCircleNum(self, isConnected: List[List[int]]) -> int:
def dfs(city):
visited[city] = True
for neighbor in range(n):
if isConnected [city][neighbor] ==1 and not visited[neighbor]:
dfs(neighbor)
n = len(isConnected)
visited = [False]*n
provinces = 0
for city in range(n):
if not visited[city]:
dfs(city)
provinces +=1
return provinces
###################################### BFS ----Solution #############################################
class Solution:
def findCircleNum(self, isConnected: List[List[int]]) -> int:
n = len(isConnected)
visited = [False]*n
provinces = 0
for city in range(n):
if not visited[city]:
queue = deque()
queue.append(city)
visited[city] = True
while queue:
current = queue.popleft()
for neighbor in range(n):
if isConnected[current][neighbor] and not visited[neighbor]:
queue.append(neighbor)
visited[neighbor] = True
provinces +=1
return provinces