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509. Fibonacci_Number_dp_solution.py
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48 lines (34 loc) · 1.09 KB
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The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,
F(0) = 0, F(1) = 1
F(n) = F(n - 1) + F(n - 2), for n > 1.
Given n, calculate F(n).
Example 1:
Input: n = 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.
Example 2:
Input: n = 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.
Example 3:
Input: n = 4
Output: 3
Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.
############################## Memoization Solution #############################
class Solution:
def fib(self, n: int) -> int:
def memo(n, dp):
if n <= 1:
return n
if n not in dp:
dp[n] = memo(n - 1, dp) + memo(n - 2, dp)
return dp[n]
dp = {}
return memo(n, dp)
############################## Tabulation Solution ##########################
class Solution:
def fib(self, n: int) -> int:
dp = [0,1]
for i in range(2, n+1):
dp.append(dp[i-1] + dp[i-2])
return dp[n]