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conditionVariableWaitForCondition.py
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142 lines (106 loc) · 3.85 KB
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"""
Copyright 2025 Huawei Technologies Co., Ltd.
Licensed under the Apache License, Version 2.0 (the "License")
you may not use this file except in compliance with the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
"""
import sys
import time
import taskr
def conditionVariableWaitForCondition(runtime):
# Contention value
value = 0
# Mutex for the condition variable
mutex = taskr.Mutex()
# Task-aware conditional variable
cv = taskr.ConditionVariable()
# Time for timeout checking (Microseconds)
timeoutTimeUs = 100 * 1000
# Forever time to wait
forever = 1000 * 1000 * 1000
def fc(task):
nonlocal value
# Using lock to update the value
print("Thread 1: I go first and set value to 1")
mutex.lock(task)
value = 1
mutex.unlock(task)
# Notifiying the other thread
print("Thread 1: Now I notify anybody waiting")
while value != 2:
cv.notifyOne(task)
task.suspend()
# Waiting for the other thread's update now
print("Thread 1: I wait (forever) for the value to turn 2")
mutex.lock(task)
wasNotified = cv.waitFor(task, mutex, lambda : value == 2, forever)
mutex.unlock(task)
if not wasNotified:
sys.stderr.write("Error: I have returned due to a timeout!")
sys.exit(1)
print("Thread 1: The condition (value == 2) is satisfied now")
# Now waiting for a condition that won't be met, although we'll get notifications
print("Thread 1: I wait (with timeout) for the value to turn 3 (won't happen)")
mutex.lock(task)
startTime = time.time_ns()*1e-3
wasNotified = cv.waitFor(task, mutex, lambda : value == 3, timeoutTimeUs)
currentTime = time.time_ns()*1e-3
elapsedTime = currentTime - startTime
mutex.unlock(task)
if wasNotified:
sys.stderr.write("Error: I have returned do to a notification!")
sys.exit(1)
if elapsedTime < timeoutTimeUs:
sys.stderr.write("Error: I have returned earlier than expected!")
sys.exit(1)
print(f"Thread 1: I've exited by timeout (as expected in {elapsedTime}us >= {timeoutTimeUs}us)")
# Updating value to 3 now, to release the other thread
mutex.lock(task)
value = 3
mutex.unlock(task)
# Creating task functions
thread1Fc = taskr.Function(fc)
def fc(task):
nonlocal value
# Waiting for the other thread to set the first value
print("Thread 2: First, I'll wait for the value to become 1")
mutex.lock(task)
wasNotified = cv.waitFor(task, mutex, lambda : value == 1, forever)
mutex.unlock(task)
if not wasNotified:
sys.stderr.write("Error: I have returned do to a timeout!")
sys.exit(1)
print("Thread 2: The condition (value == 1) is satisfied now")
# Now updating the value ourselves
print("Thread 2: Now I update the value to 2")
mutex.lock(task)
value = 2
mutex.unlock(task)
# Notifying the other thread
print("Thread 2: Notifying constantly until the value is 3")
while value != 3:
cv.notifyOne(task)
task.suspend()
thread2Fc = taskr.Function(fc)
task1 = taskr.Task(0, thread1Fc)
task2 = taskr.Task(1, thread2Fc)
runtime.addTask(task1)
runtime.addTask(task2)
# Initializing taskr
runtime.initialize()
# Running taskr
runtime.run()
# Waiting for task to finish
runtime.wait()
# Finalizing taskr
runtime.finalize()
# Value should be equal to concurrent task count
expectedValue = 3
print(f"Value {value} / Expected {expectedValue}")
assert value == expectedValue